Java判断IP在属于ip段

来源：互联网发布：p2p按天返利的理财源码编辑：程序博客网时间：2024/05/16 19:41

问题是这样的，输入一个IP地址，先判断一下该IP是否是合法的IP地址，然后再判断该IP地址是否在一个相应的IP段内
开始IP为beginIp，结束问题是这样的，输入一个IP地址，先判断一下该IP是否是合法的IP地址，然后再判断该IP地址是否在一个相应的IP段内

public class ipTest {       /**       * 判断IP是否在指定范围；       */              public static boolean ipIsValid(String ipSection, String ip) {           if (ipSection == null)               throw new NullPointerException("IP段不能为空！");           if (ip == null)               throw new NullPointerException("IP不能为空！");           ipSection = ipSection.trim();           ip = ip.trim();           final String REGX_IP = "((25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)\\.){3}(25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)";           final String REGX_IPB = REGX_IP + "\\-" + REGX_IP;           if (!ipSection.matches(REGX_IPB) || !ip.matches(REGX_IP))               return false;           int idx = ipSection.indexOf('-');           String[] sips = ipSection.substring(0, idx).split("\\.");           String[] sipe = ipSection.substring(idx + 1).split("\\.");           String[] sipt = ip.split("\\.");           long ips = 0L, ipe = 0L, ipt = 0L;           for (int i = 0; i < 4; ++i) {               ips = ips << 8 | Integer.parseInt(sips[i]);               ipe = ipe << 8 | Integer.parseInt(sipe[i]);               ipt = ipt << 8 | Integer.parseInt(sipt[i]);           }           if (ips > ipe) {               long t = ips;               ips = ipe;               ipe = t;           }           return ips <= ipt && ipt <= ipe;       }       public static void main(String[] args) {           if (ipIsValid("192.168.1.1-192.168.1.10", "192.168.3.54")) {               System.out.println("ip属于该网段");           } else              System.out.println("ip不属于该网段");       }   }

0 0