不能被继承的类

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/**********************************************************************题目：用C++设计一个不能被继承的类**********************************************************************/#include <stdio.h>// ====================方法一====================//常规的方法：把构造函数设为私有函数class SealedClass1{public:    static SealedClass1* GetInstance()     {        return new SealedClass1();    }     static void DeleteInstance( SealedClass1* pInstance)    {        delete pInstance;    } private:    SealedClass1() {}    ~SealedClass1() {}};// 如果试图从SealedClass1继承出新的类型，// 将会导致编译错误。/*class Try1 : public SealedClass1{public:    Try1() {}    ~Try1() {}};*/// ====================方法二====================//利用虚拟继承template <typename T> class MakeSealed{    friend T; private:    MakeSealed() {}    ~MakeSealed() {}}; class SealedClass2 : virtual public MakeSealed<SealedClass2>{public:    SealedClass2() {}    ~SealedClass2() {}};// 如果试图从SealedClass1继承出新的类型，// 将会导致编译错误。/*class Try2 : public SealedClass2{public:    Try2() {}    ~Try2() {}};*/int main(){    return 0;}

==参考剑指offer

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