488 - Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below.This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

132

Sample Output

122333221122333221

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Note:红字部分是神坑，直接cin就可以了，不用加空行，绿色是重点：每个case都要输入参数，而输出跟在后面，最后的三角波不用空行

#include <iostream>using namespace std;void print(int n,int upORdown){     if (upORdown == 1)       //打印上半部分     {      int i = 1;      for (i;i <= n;i++)         {          int j = 0;          for (j;j < i;j++)            cout << i;           cout << endl;             }          }     else                   //打印下半部分     {      int i = n-1;      for (i;i >= 1;i--)          {          int j = 0;          for (j;j < i;j++)            cout << i;          cout << endl;         }     }}int main(){    int cases,amplitude,frequency;    cin  >> cases;    while (cases)        {          cin  >> amplitude;          cin  >> frequency;          int temp = frequency;          while (temp)          {            print(amplitude,1);            print(amplitude,0);             if (temp != 1)       //最后的三角波不用空行               cout << endl;                   temp--;               }          if(cases > 1)                      cout << endl;           cases--;         }    return 0;    }