判断LBP值是否为uniform

来源：互联网发布：facebook自动加人软件编辑：程序博客网时间：2024/06/07 01:05

LBP值是0~255之间的数值，uniform指的是其二进制形式的翻转次数是否超过2次，比如"00001110" 为unifom，而“00110011”不是uniform.

#include <iostream>using namespace std;//#define _DEBUG_INFOvoid printBinary(const unsigned char val){for(int i = 7; i >= 0; i--){if(val & (1 << i))cout << "1";elsecout << "0";}}bool IsUniform(const unsigned char val){int bit = 0;int last_bit = 0;int change_time = 0;if(val & (1 << 7))bit = 1;elsebit = 0;last_bit = bit;for(int i = 6; i >= 0; i--){if(val & (1 << i))bit = 1;elsebit = 0;if(bit != last_bit)change_time ++;last_bit = bit;}#ifdef _DEBUG_INFOprintf("change_time = %d\n", change_time);#endif //_DEBUG_INFOif(change_time <= 2)return true;elsereturn false;}int uniform_table[256] = {1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1,};int main(int argc, char* argv[]){int val = atoi(argv[1]);printBinary(val);cout << endl;if(IsUniform(val))cout << "Uniform" << endl;elsecout << "Not uniform" << endl;printf("uniform_table[%d] = %d\n", val, uniform_table[val]);//int uniform_cnt = 0;//for(int i = 0; i <= 255; i++){//if(IsUniform(i)){//cout << "1, ";//uniform_cnt ++;//}//else//cout << "0, ";//if((i+1)%16 == 0)//cout << endl;//}//cout << "\n uniform_cnt = " << uniform_cnt << endl;}

函数IsUniform判断某LBP值是否为uniform。最后列出了一个uniform_table直接查询某LBP值是否为uniform.

0 0