HDU 1506 Largest Rectangle in a Histogram(dp)
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题目链接:HDU 1506 Largest Rectangle in a Histogram
对于每一块木板,Area=height[i]*(j-k+1) 设其中任一块x, j<=x<=k, height[x]>=height[i]; 找j,k成为关键。
利用动态规划,如果它左边高度大于等于它本身,那么它左边的左边界一定满足这个性质,再从这个边界的左边迭代下去。左边界迭代完再迭代右边界。
在杭电提交了好多次都是TLE,c++输入输出改成c的输入输出,long long,__int64换着提交,怎么都不行,最后提交方式由g++改成了c++。。过了。。。
#include <iostream>using namespace std;const int MAX_N = 100000 + 100;long long arr[MAX_N];//__int64 arr[MAX_N];int l[MAX_N],r[MAX_N];int n;int main(){ while(cin >> n,n) { for(int i = 1;i <= n;i++) { cin >> arr[i]; l[i] = r[i] = i; } for(int i = 1;i <= n;i++) { while(l[i] - 1 > 0 && arr[l[i] - 1] >= arr[i]) { l[i] = l[l[i] - 1]; } } for(int i = n;i > 0;i--) { while(r[i] + 1 <= n && arr[r[i] + 1] >= arr[i]) { r[i] = r[r[i] + 1]; } } long long _max = 0; //__int64 _max = 0; for(int i = 1;i <= n;i++) _max = max(_max,(r[i] - l[i] + 1) * arr[i]); cout << _max << endl; } return 0;}
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