HDU 2123 An easy problem

Problem Description

In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the i^th row and j^th column should be the product(乘积) of i and j.

 

Input

The first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.

 

Output

For each test case, print out the multiply table.

 

Sample Input

214

 

Sample Output

11 2 3 42 4 6 83 6 9 124 8 12 16
#include<stdio.h>  //int a[10][10];int main()  {      int n,t,i,j;      char c;  scanf("%d",&t);    while(t--)      {  scanf("%d",&n);       for(i=1;i<=n;i++)   {   for(j=1;j<=n;j++)   {//   a[i][j]=i*j;   if(j<n)   printf("%d ",i*j);   else   printf("%d",i*j);   }   printf("\n");   }    }      return 0;  }