senchatouch 与PHP后台数据交互

ST 可以把数据包装成json格式发送到php端

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1. cartItemsStore = Ext.getStore('cartitemsconvert');  
2.                 var allData = [];  
3.                 cartItemsStore.each(function(records){  
4.                     allData.push(records.getData());  
5.                 });  
6.                 var dataToBeSentToServer = Ext.JSON.encode(allData);  
7.                 console.log(dataToBeSentToServer);  

然后用jsonp或是ajax将数据传输到PHP端

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1. Ext.data.JsonP.request({  
2.                     url: 'http://londit-50c03e41547f8.com.1130.url-test.com/dingcan/php/save-orders.php',  
3.                     callbackKey: 'callback',  
4.                     params: {  
5.                         sendData:dataToBeSentToServer  
6.                     },  
7.                     timeout:2000,  
8.                     success: function(result, request) {  
9.                         console.log('提交数据成功');  
10.                     }  
11.                 });  

然后PHP怎么获得这些json数据呢？红色部分是php的问题。如果不用stripslashes转换。stripslashes() 函数删除由 addslashes() 函数添加的反斜杠。否则数据打印出来是空，还有个解决办法就是：The fix was to turn off magic_quotes in php.ini. If you do this, you will no longer need the call to stripslashes(). 

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1. $sendData = $_REQUEST['sendData'];  
2. <span style="color:#ff0000;">$jsondata = stripslashes($sendData);</span>  
3. //$sendData = '[{"id":"1","food":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","food":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';  
4. $arrayData = json_decode($jsondata);  
5. foreach($arrayData as $obj){  
6.     echo "id：".$obj->food."<br />";  
7. }  

另外附上PHP两种解析json数据的方法：

在PHP代码中处理JSON 格式的字符串的两种方法：唯一不同已经highlight出来了

方法一：

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1. $json ='[{"id":"1","name":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","name":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';  
2. <span style="color:#ff0000;">$students = json_decode($json);//得到的是 object</span>  
3. foreach($students as $obj){  
4. echo "姓名：".$obj->name."年龄：".$obj->age." 专业：".$obj->subject."<br/>";  
5. }  

方法二：

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1. $json ='[{"id":"1","name":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280\u672f"},{"id":"2","name":"\u5f20\u6c9b\u9716","age":"21","subject":"\u8f6f\u4ef6\u5de5\u7a0b"}]';  
2. <span style="color:#ff0000;">$students = json_decode($json, </span><span style="color:#33ff33;">true</span><span style="color:#ff0000;">);//得到的是 array</span>  
3. for($i=0;$i<count($students);$i++){  
4. echo "姓名：".$students[$i]['name']."年龄：".$students[$i]['age']."专业：".$students[$i]['subject']."<br />";  
5. }