整形数组的异集

求两个整型数组的异集，即A+B-(A与B的交集)

vector<int> XorSet(vector<int> a, vector <int>b){vector<int>result;vector<int>::const_iterator pos;vector<int>::iterator iter=b.begin();//vector<int>::iterator temp;while(iter != b.end()){pos = find(a.begin(), a.end(),*iter);if (pos != a.end()){//temp = iter;a.erase(pos);iter=b.erase(iter);}else{++iter;}}result.insert(result.end(), a.begin(), a.end());result.insert(result.end(), b.begin(), b.end());return result;}

测试用例

[1,2,3,4]

[2,3,7,8]

int main(){vector<int> v1 = { 1, 2, 3, 4 };vector<int> v2 = { 2, 3, 7, 8 };vector<int> v3 = XorSet(v1, v2);for (vector<int>::iterator  iter= v3.begin(); iter != v3.end(); iter++){cout <<*iter << endl;}return 0;}