ASP.NET中Request.InputStream使用

来源：互联网发布：dx修复软件官网编辑：程序博客网时间：2024/05/05 11:39

将数据作为XML数据发送,例如:

public void PostXml(string url, string xml) {    byte[] bytes = Encoding.UTF8.GetBytes(xml);    HttpWebRequest request = (HttpWebRequest) WebRequest.Create(url);    request.Method = "POST";    request.ContentLength = bytes.Length;    request.ContentType = "text/xml";    using (Stream requestStream = request.GetRequestStream()) {      requestStream.Write(bytes, 0, bytes.Length);    }   HttpWebResponse response = (HttpWebResponse) request.GetResponse();    if (response.StatusCode != HttpStatusCode.OK) {      string message = String.Format("POST failed. Received HTTP {0}",      response.StatusCode);      throw new ApplicationException(message);    } }

接收端通过Request.InputStream读取:

byte[] byts = new byte[Request.InputStream.Length]; Request.InputStream.Read(byts,0,byts.Length); string req = System.Text.Encoding.Default.GetString(byts); req = Server.UrlDecode(req);

对于完整的XML数据,可以:

xmlDoc = new XmlDocument(); xmlDoc.load(Request.InputStream);

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