HDOJ 1250 Hat's Fibonacci

1.Hat's Fibonacci

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6559    Accepted Submission(s): 2178

Problem Description

A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.

 

Input

Each line will contain an integers. Process to end of file.

 

Output

For each case, output the result in a line.

 

Sample Input

100

 

Sample Output

4203968145672990846840663646Note:No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.

 2.源码

#include <stdio.h>#include <string.h>int main(){int i=1,j,n,jin,m,s;int a[5][260];//只用五行做空间，选一行为当前计算行。while(scanf("%d",&n)!=EOF){memset(a,0,sizeof(a));a[1][0]=a[2][0]=a[3][0]=a[4][0]=1;for(i=5;i<=n;i++){jin=0;m=i%5;for(j=0;j<260;j++){s=a[0][j]+a[1][j]+a[2][j]+a[3][j]+a[4][j]+jin-a[m][j];jin=s/100000000;//不是按照10位进位，而是按照8位一进位。a[m][j]=s%100000000;}}i=259;while(!a[n%5][i])   i--;printf("%d",a[n%5][i]);//头8位可能不足8位提前输出。i--;while(i>=0){printf("%08d",a[n%5][i]);i--;}printf("\n");//注意别忘了换行.}return 0;}

根据看到两个代码综合一下，感觉还不错。