UVaOJ_10405 - Longest Common Subsequence

Problem C: Longest Common Subsequence

Sequence 1:                

Sequence 2:                


Given two sequences of characters, print the length of the longest common subsequence of both sequences. For example, the longest common subsequence of the following two sequences:

abcdghaedfhr

is adh of length 3.

Input consists of pairs of lines. The first line of a pair contains the first string and the second line contains the second string. Each string is on a separate line and consists of at most 1,000 characters

For each subsequent pair of input lines, output a line containing one integer number which satisfies the criteria stated above.

Sample input

a1b2c3d4ezz1yy2xx3ww4vvabcdghaedfhrabcdefghijklmnopqrstuvwxyza0b0c0d0e0f0g0h0i0j0k0l0m0n0o0p0q0r0s0t0u0v0w0x0y0z0abcdefghijklmnzyxwvutsrqpoopqrstuvwxyzabcdefghijklmn

Output for the sample input

432614

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Problem Setter: Piotr Rudnicki

注意数组越界，字符串中可以包含空格，所以写输入模块时要注意，不然就是Wrong answer！！！

#include <stdio.h>#include <string.h>int fun();char ch1[1010];char ch2[1010];int LCS[1010][1010];int main(){while(fgets(ch1, 1010, stdin) && fgets(ch2, 1010, stdin)){printf("%d\n", fun());}}int fun(){int len1 = strlen(ch1) - 1;int len2 = strlen(ch2) - 1;int i, j;memset(LCS, 0, sizeof(LCS)); for(i = 1; i <= len1; i++)for(j = 1; j <= len2; j++){if(ch1[i-1] == ch2[j-1])LCS[i][j] = LCS[i-1][j-1] + 1;else if(LCS[i-1][j] >= LCS[i][j-1])LCS[i][j] = LCS[i-1][j];elseLCS[i][j] = LCS[i][j-1];}return LCS[len1][len2];}