【LeetCode】Maximum Subarray
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参考链接
http://blog.csdn.net/magisu/article/details/14515209题目描述
Maximum Subarray
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4]
,
the contiguous subarray [4,−1,2,1]
has the largest sum = 6
.
click to show more practice.
More practice:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
题目分析
题目是意思是,找出一个子串,要求子串中数字之和最大。
这是一个经典的动态规划的题目,需要了解以下规律。
max_subarray(A[n]) = max( max_subarray(A[n-1]), A[n], max_subarray(A[n-1)(+)A[n] );
最大子串和是之前已经遍历过的数字中的最大值max_subarray(A[n-1]),当前值A[n],和加上当前值max_subarray(A[n-1)(+)A[n]这三者之间的最大值。
代码示例
推荐学习C++的资料
C++标准函数库
http://download.csdn.net/detail/chinasnowwolf/7108919
在线C++API查询
http://www.cplusplus.com/
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