2014-04-13第15周周日：goto语句的标志只包含一句话，而且程序总会执行goto的标志。

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对于下面这段代码，

int main(){int i, j;for ( i = 0; i < 10; i++ ){printf( "Outer loop executing. i = %d\n", i );for ( j = 0; j < 3; j++ ){printf( " Inner loop executing. j = %d\n", j );if ( i == 10 )goto stop;printf( " i = %d , j = %d \n",i, j );}}/* This message does not print: */printf( "Loop exited. i = %d\n", i );stop: printf( "Jumped to stop. i = %d\n", i );//stop: 就是标签  return 0;}

最后两行显示的是：

Loop exited. i =10Jumped to stop.i=10

可见，程序未执行goto stop;这条语句，但还是经过了stop的标志。

以下代码是执行了goto stop;这条语句并跳到stop标志处的情况（只是将以上程序的if(i==5)改成了if(i==10)）：

#include <stdio.h>int main(){int i, j;for ( i = 0; i < 10; i++ ){printf( "Outer loop executing. i = %d\n", i );for ( j = 0; j < 3; j++ ){printf( " Inner loop executing. j = %d\n", j );if ( i == 5 )goto stop;printf( " i = %d , j = %d \n",i, j );}}/* This message does not print: */printf( "Loop exited. i = %d\n", i );stop: printf( "Jumped to stop. i = %d\n", i );//stop: 就是标签  return 0;}

最后三行显示的是：

Outer loop executing. i=5Inner loop executing. j=0Jumped to stop. i=5

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