实现复数类中的运算符重载3

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/**Corpyright (c)2013,烟台大学计算机学院*All right reseved.*作者：z张梦佳*完成日期：2014年4月14日*版本号：v1.0*输入描述：*问题描述:复shu类！*程序输出：*问题分析：*算法设计：*/#include <iostream>#include <cmath>using namespace std;class Complex{public:    Complex(){real=0;imag=0;}    Complex(double r,double i){real=r; imag=i;}    Complex operator+(double a);    Complex operator-(double a);    friend Complex operator+(double x,Complex c);    friend Complex operator-(double x,Complex c);    void display();    double geta()    {        return real;    }    double getb()    {        return imag;    }private:    double real;    double imag;};//下面定义成员函数Complex Complex::operator+(double a){    return Complex(a+real,imag);}Complex Complex::operator-(double a){    return Complex(a-real,imag);}void Complex::display(){    cout<<"("<<real<<","<<imag<<")"<<endl;}int main(){    Complex c1(3,4),c2;    double d=10;    cout<<"c1+d"<<endl;    c2=c1+d;    c2.display();    cout<<"c1-d"<<endl;    c2=c1-d;    c2.display();    cout<<"d+c1"<<endl;    c2=d+c1;    c2.display();    cout<<"d-c1"<<endl;    c2=d-c1;    c2.display();    return 0;}Complex operator+(double x,Complex c){    return Complex(x+c.real,c.imag);}Complex operator-(double x,Complex c){    return Complex(x-c.real,c.imag);}

感悟

这个题告诉我，平时认为理所当然的事也有很多漏洞。

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