实现复数类的运算符重载

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/** 程序的版权和版本声明部分:* Copyright (c) 2013, 烟台大学计算机学院* All rights reserved.* 文件名称：test.cpp* 作    者：周经纬* 完成日期：2014年 4月 15日* 版 本 号：v12.1* 实现复数类中运算符重载，* 输入描述：无* 问题描述：。* 程序输出：* 问题分析：略* 算法设计：略*/#include <iostream>using namespace std;class Complex{public:    Complex()    {        real=0;        imag=0;    }    Complex(double r,double i)    {        real=r;        imag=i;    }    Complex operator+(Complex &c2);    Complex operator-(Complex &c2);    Complex operator*(Complex &c2);    Complex operator/(Complex &c2);    void display();private:    double real;    double imag;};//下面定义成员函数void Complex::display(){    cout<<"("<<real<<","<<imag<<"i)"<<endl;}Complex Complex::operator+(Complex &c2){    return Complex(real+c2.real,imag+c2.imag);}Complex Complex::operator-(Complex &c2){    return Complex(c2.real-real,c2.imag-imag);}Complex Complex::operator*(Complex &c2){    Complex c;    c.real=real*c2.real+imag*c2.imag;    c.imag=real*c2.imag+imag*c2.real;    return c;}Complex Complex::operator/(Complex &c2){    Complex c;    c.real=(real*c2.real-imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    c.imag=(imag*c2.real-real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    return c;}//下面定义用于测试的main()函数int main(){    Complex c1(3,4),c2(5,-10),c3;    cout<<"c1=";    c1.display();    cout<<"c2=";    c2.display();    c3=c1+c2;    cout<<"c1+c2=";    c3.display();    c3=c1-c2;    cout<<"c1-c2=";    c3.display();    c3=c1*c2;    cout<<"c1*c2=";    c3.display();    c3=c1/c2;    cout<<"c1/c2=";    c3.display();    return 0;}

感悟：直接用return语句返回结果简单明了很多呢

呵呵

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