八周 项目2 Time类中的运算符重载

/**程序的版权和版本声明部分：*Copyright(c)2014，烟台大学计算机学院学生*All rights reserved.*文件名称:*作者：赵加响*完成日期：2014  年 4月 15 日*版本号：v1.0*对任务及求解方法的描述部分：*输入描述：无*问题描述：*程序输出：*问题分析：*算法设计：*/#include <iostream>using namespace std;class CTime{private:    unsigned short int hour;    // 时    unsigned short int minute;  // 分    unsigned short int second;  // 秒public:    CTime(int h=0,int m=0,int s=0);    void setTime(int h,int m,int s);    void display();    //二目的比较运算符重载    bool operator > (CTime &t);    bool operator < (CTime &t);    bool operator >= (CTime &t);    bool operator <= (CTime &t);    bool operator == (CTime &t);    bool operator != (CTime &t);    //二目的加减运算符的重载    //返回t规定的时、分、秒后的时间，例t1(8,20,25),t2(11,20,50)，t1+t2为:41:15    CTime operator+(CTime &t);    CTime operator-(CTime &t);//对照+理解    CTime operator+(int s);//返回s秒后的时间    CTime operator-(int s);//返回s秒前的时间    //二目赋值运算符的重载    CTime operator+=(CTime &c);    CTime operator-=(CTime &c);    CTime operator+=(int s);//返回s秒后的时间    CTime operator-=(int s);//返回s秒前的时间};//下面实现所有的运算符重载代码。CTime::CTime(int h,int m,int s){    hour=h;    minute=m;    second=s;}void CTime::setTime(int h,int m,int s){    hour=h;    minute=m;    second=s;}void CTime::display(){    cout<<hour<<":"<<minute<<":"<<second<<endl;}bool CTime::operator > (CTime &t){    if(hour>t.hour)        return true;        else            return false;    if(minute>t.minute)        return true;        else            return false;    if(second>t.second)        return true;        else            return false;}bool CTime::operator < (CTime &t){    if(hour<t.hour)        return true;        else            return false;    if(minute<t.minute)        return true;        else            return false;    if(second<t.second)        return true;        else            return false;}bool CTime::operator >= (CTime &t){    if(*this<t)return true;    return false;}bool CTime::operator <= (CTime &t){    if(*this>t)return true;    return false;}bool CTime::operator == (CTime &t){    if(*this>t||*this<t)return true;    return false;}bool CTime::operator != (CTime &t){    if(*this==t)return true;    return false;}CTime CTime::operator+(CTime &t){    int h,m,s;    h=hour+t.hour;    m=minute+t.minute;    s=second+t.second;    if(s>59)    {        s-=60;    m++;    }    if(m>59)    {        m-=60;    h++;    }    if(h>24)    {        h-=24;    }    CTime t0(h,m,s);    return t0;}CTime CTime::operator+(int s){    int ss=s%60;    int mm=(s/60)%60;    int hh=s/3600;    CTime t0(hh,mm,ss);    return *this+t0;}CTime CTime::operator-(CTime &t){    int h,m,s;    h=hour-t.hour;    m=minute-t.minute;    s=second-t.second;    if(s<0)    {        s+=60;         m--;    }    if(m<0)    {        m+=60;        h--;    }    if(h<0)    {        h+=24;    }    CTime t0(h,m,s);    return t0;}CTime CTime::operator-(int s){    int ss=s%60;    int mm=(s/60)%60;    int hh=s/3600;    CTime t0(hh,mm,ss);    return *this-t0;}CTime CTime::operator+=(CTime &c){    *this=*this+c;    return *this;}CTime CTime::operator+=(int s){    *this=*this+s;    return *this;}CTime CTime::operator-=(CTime &c){    *this=*this-c;    return *this;}CTime CTime::operator-=(int s){    *this=*this-s;    return *this;}//自行编制用于测试的main()函数，有些结果不必依赖display()函数，提倡用单步执行查看结果int main(){    CTime t1(8,8,8),t2,t3,t4,t5,t6;    int a,b,c,s1,s2;    char m1,m2;    cout<<"c1:";    t1.display();    cout<<"输入时间 t2："<<endl;    while(1)    {    cin>>a>>m1>>b>>m2>>c;    if(a>24||a<0||b>24||b<0||c>24||c<0)    cout<<"输入时间不对！重新输入："<<endl;    else if(m1!=':'||m2!=':')    cout<<"时间格式不对！重新输入："<<endl;    else    break;    }    t2.setTime(a,b,c);    cout<<"t2: ";    t2.display();    cout<<endl;    if (t1>t2) cout<<"t1>t2"<<endl;    if (t1<t2) cout<<"t1<t2"<<endl;    if (t1==t2) cout<<"t1＝t2"<<endl;    if (t1!=t2) cout<<"t1≠t2"<<endl;  //“≠”是怎么打出来的？？    if (t1>=t2) cout<<"t1≥t2"<<endl;    if (t1<=t2) cout<<"t1≤t2"<<endl;    cout<<endl;    t3=t1+t2;    cout<<"t1+t2: ";    t3.display();    t4=t1-t2;    cout<<"t1+t2: ";    t4.display();    cout<<"输入要t2增加的秒数："<<endl;    cin>>s1;    t5=t2+s1;    cout<<"t2增加"<<s1<<"秒: ";    t5.display();    cout<<"输入要t1减少的秒数："<<endl;    cin>>s2;    t6=t2-s2;    cout<<"t1减少"<<s2<<"秒: ";    t6.display();}

感悟：哎呀！妈呀，好难！尽管程序中大部分都是看的老师的，但我也有增加一些。虽是借鉴，但不容易，且学且珍惜。