[codility]PermCheck
来源:互联网 发布:elliott smith 知乎 编辑:程序博客网 时间:2024/06/06 05:44
Python代码如下:
def solution(A): # write your code in Python 2.6 checkTable = [False]*len(A) for value in A: if value < 1 or value > len(A): return 0 checkTable[value-1] = True for flag in checkTable: if not flag: return 0 return 1 pass
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