第二学期第八周项目1--实现复数类中的运算符重载

以下是我将类模板和重载结合起来的代码，可是会报错。张玉老师让问老贺。

/* * Copyright (c) 2013, 烟台大学计算机学院 * All rights reserved. * 作    者：  沈远宏 * 完成日期：2013 年 04月15日 * 版 本 号：v1.0 * 问题描述：一个定义完整的类，是可以当作独立的产品发布，成为众多项目中的“基础工程”，这样的类在方案二的基础上，             扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d;c+d和d+c的结果             为“将d视为实部为d的复数同c相加”，其他-、*、/运算符类似。 * 输出：两个复数+，-，*，/后的结果输出*/#include <iostream>using namespace std;template <class numtype>class Complex{public:    Complex(numtype r,numtype i)    {        real=r;        imag=i;    }    Complex<numtype> operator+(numtype &d);    Complex<numtype> operator+(numtype &d,Complex <numtype>&c);    Complex<numtype> operator-(Complex <numtype>&c, numtype&d);    Complex<numtype> operator-(numtype &d,Complex<numtype> &c);    Complex<numtype> operator*(Complex<numtype> &c, numtype &d);    Complex<numtype> operator*(numtype &d,Complex<numtype> &c);    Complex<numtype> operator/(Complex<numtype> &c, numtype &d);    Complex<numtype> operator/(numtype &d,Complex<numtype> &c);    void set(numtype a,numtype b);    void display();private:    numtype real;    numtype imag;};//下面定义成员函数template <class numtype>Complex Complex<numtype>::operator+(Complex<numtype> &c, numtype &d)//+{    return Complex(d+c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator+(numtype &d,Complex<numtype> &c){    return Complex(d+c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator-(Complex <numtype>&c, numtype &d)//-{    return Complex(d-c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator-(numtype &d,Complex<numtype> &c){    return Complex(d-c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator*(Complex<numtype> &c, numtype &d)//*{    return Complex(d*c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator*(numtype &d,Complex<numtype> &c){    return Complex(d*c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator/(Complex<numtype> &c, numtype &d)// /{    return Complex(d/c.real,c.imag);}template <class numtype>Complex Complex<numtype>::operator/(numtype &d,Complex<numtype> &c){    return Complex(d/c.real,c.imag);}void Complex::display(){    cout<<real<<"+"<<"("<<imag<<")i\n";}template <class numtype>void Complex<numtype>::set(numtype a,numtype b){    real=a;    imag=b;}//下面定义用于测试的main()函数int main(){    Complex<int>c1,c3;    int d;    cout<<"请依次输入附属的实部和虚部\n(整型)";    cin>>a>>b;    c1.set(a,b);    cout<<"c1=";    c1.display();    cout<<"请输入一个整型数：\n";    cin>>d;    cout<<"c1+d=";    c3=d+c1;    c3.display();    cout<<"c1-d=";    c3=c1-d;    c3.display();    cout<<"c1*d=";    c3=d*c1;    c3.display();    cout<<"c1/d=";    c3=c1/d;    c3.display();    Complex<double>c2,c4;    double a1,b1,d1;    cout<<"请依次输入附属的实部和虚部\n(浮点型)";    cin>>a1>>b1;    c2.set(a1,b1);    cout<<"c2=";    c2.display();    cout<<"请输入一个浮点数：\n";    cin>>d1;    cout<<"d1+c2=";    c4=d1+c2;    c4.display();    cout<<"d1-c2=";    c4=d1-c2;    c4.display();    cout<<"d1*c2=";    c4=d1*c2;    c4.display();    cout<<"d1/c2=";    c4=d1/c2;    c4.display();    return 0

}

下面只重载double的代码：

/* * Copyright (c) 2013, 烟台大学计算机学院 * All rights reserved. * 作    者：  沈远宏 * 完成日期：2013 年 04月15日 * 版 本 号：v1.0 * 问题描述：一个定义完整的类，是可以当作独立的产品发布，成为众多项目中的“基础工程”，这样的类在方案二的基础上，             扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d;c+d和d+c的结果             为“将d视为实部为d的复数同c相加”，其他-、*、/运算符类似。 * 输出：两个复数+，-，*，/后的结果输出*/#include <iostream>using namespace std;class Complex{public:     Complex()    {        real=0;        imag=0;    }    Complex(double r,double i)    {        real=r;        imag=i;    }    friend Complex operator+( Complex &c,double &d);    friend Complex operator+(double &d,Complex &c);    friend Complex operator-(double &d,Complex &c);    friend Complex operator-(Complex &c,double &d);    friend Complex operator*(Complex &c, double &d);    friend Complex operator*( double &d,Complex &c);    friend Complex operator/(Complex &c,double &d);    friend Complex operator/( double &d,Complex &c);    void set(double a,double b);    void display();private:    double real;    double imag;};//下面定义成员函数Complex operator+(Complex &c, double  &d)//+{    return Complex(d+c.real,c.imag);}Complex operator+(  double&d,Complex &c){    return Complex(d+c.real,c.imag);}Complex operator-(Complex &c ,double &d)//-{    return Complex(d-c.real,c.imag);}Complex operator-(  double&d,Complex &c){    return Complex(d-c.real,c.imag);}Complex operator*(Complex &c,  double &d)//*{    return Complex(d*c.real,c.imag);}Complex operator*(  double&d,Complex &c){    return Complex(d*c.real,c.imag);}Complex operator/(Complex &c, double &d)// /{    return Complex(d/c.real,c.imag);}Complex operator/(  double&d,Complex &c){    return Complex(c.real/d,c.imag);}void Complex::display(){    cout<<real<<"+"<<"("<<imag<<")i\n";}void Complex::set( double a, double b){    real=a;    imag=b;}//下面定义用于测试的main()函数int main(){    Complex c1(3.0,4.0),c3;    double d=5.0;    cout<<"c1=";    c1.display();    c3=c1+d;    cout<<"c1+d=";    c3.display();    c3=c1-d;    cout<<"c1-d=";    c3.display();    c3=c1*d;    cout<<"c1*d=";    c3.display();    c3=c1/d;    cout<<"c1/d=";    c3.display();    c3=d+c1;    cout<<"d+c1=";    c3.display();    c3=d-c1;    cout<<"d-c1=";    c3.display();    c3=d*c1;    cout<<"d*c1=";    c3.display();    c3=d/c1;    cout<<"d/c1=";    c3.display();    return 0;}

运行结果：

心得体会：

总觉得C++是个蹊跷的东西，内幕很多哦~~