Longest Palindromic Substring (c++)
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题目:Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.
问题描述:求一个字符串里最长的回文串
回文串:回文串是具有回文特性的字符串,即该字符串从左向右读,与从右向左读都一样。例如:abcdcba.
解题思路:遍历字符串,以字符串为中心,检测两侧是否对称,如果对称则有回文串,统计长度,求出最长的串。求解中有两种情况:回文串字符个数为奇数“abcdcba”,关于中心对称,回文串字符个数为偶数“abcddcba”两侧都对称。
代码如下:
class Solution {public: string palindrome_detect(string &s,int l,int r) //回文串检测函数 { if(l<0) return s.substr(0,1);//左侧溢出处理 if(r>=s.size()) return s.substr(r-1,1); //右侧溢出处理 while(0<=l && r< s.size()) { if(s[l]!=s[r]) break; l--; r++; } l++; r--; return s.substr(l,r-l+1); } string longestPalindrome(string s) { int len=s.length(); if(len==0) return ""; string res; for(int i=0;i<len;i++) { string temp=palindrome_detect(s,i-1,i+1); //回文串字符个数为奇数 if(temp.size()>res.size()) res=temp; temp=palindrome_detect(s,i,i+1); //回文串字符个数为偶数 if(temp.size()>res.size()) res=temp; } return res; } };
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