dev-C++五子棋

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学搜索的时候写了练手的。。
/* -------------------------------- *        c++ code              * * by Lytning 2013/08/01 17:50  * --------------------------------*/#include <iostream>#include <conio.h>#define clr system("cls")#define inside(x,y) ((x>0)&&(y>0)&&(x<16)&&(y<16))using namespace std;int pan[16][16],nums[4],x,y,oldx,oldy;bool isBlack;void instruction(int i){    if(i==1)     {        cout<<"Dev-C++ 五子棋 - Welcome"<<endl;         cout<<"---------------------------"<<endl;        cout<<"· 该程序为双人五子棋，无人机对战"<<endl;         cout<<"· 输入“S”开始游戏"<<endl;        cout<<"· 需要指令控制游戏，输入“?”获取帮助"<<endl;        cout<<"                    powered by Lytning"<<endl;    }    if(i==2)     {        cout<<"---------------------------"<<endl;        cout<<"Dev-C++ 五子棋 - 指令"<<endl;        cout<<"---------------------------"<<endl;        cout<<"由于是控制台程序，需要输入指令控制游戏"<<endl;        cout<<"指令列表："<<endl;        cout<<"·N(空格)x(空格)y   ：将棋子下在(x,y)位置。"<<endl;        cout<<"棋盘中坐标以16进制显示，输入时请输入10进制坐标。(A=10,F=15)"<<endl;        cout<<"·A(空格)指令(空格)n：将棋子下在当前棋子附近n个单位"<<endl;        cout<<"指令: R-右侧  L-左侧  U-上方  D-下方"<<endl;        cout<<"RD-右下 RU-右上 LD-左下 LU-左上"<<endl;         cout<<"例如:A R 1：将棋子下在当前棋子 右侧 1 个单位"<<endl;        cout<<" A LD 3:将棋子下在当前棋子左下方 3 个单位"<<endl;         cout<<"tips:开局时可随意输入一个n为0的指令在棋盘中央下棋"<<endl;         cout<<"         例如: A L 0"<<endl;     }}char makech(int n){    if(n<10)        return (char)n+48;    return (char)n+55;}void print(){    cout<<"   ";    for(int i=1;i<16;i++)        cout<<makech(i)<<" ";    cout<<endl<<"  ------------------------------"<<endl;    for(int i=1;i<16;i++)    {        for(int j=1;j<16;j++)        {            if(j==1)                cout<<makech(i)<<"| ";            switch(pan[i][j])            {                case 9:                    cout<<"- ";                    break;                case 0:                    cout<<"0 ";                    break;                case 1:                    cout<<"1 ";                    break;            }        }        cout<<endl;    }}void dfs2(int x,int y,int fx){    int trues=isBlack?1:0;    if(pan[x][y]==trues)        {nums[fx]++; }    else        {return;}    switch(fx)    {        case 0:            if(inside(x+1,y))                {dfs2(x+1,y,0);}            else                {return;}            break;        case 1:            if(inside(x,y+1))                {dfs2(x,y+1,1);}            else                {return;}            break;        case 2:            if(inside(x+1,y+1))                {dfs2(x+1,y+1,2);}            else                {return;}            break;        case 3:            if(inside(x+1,y-1))                {dfs2(x+1,y-1,3);}            else                {return;}            break;    }}void dfs1(int x,int y,int fx)//0 上下 1 左右 2 ＼  3／ {    int trues=isBlack?1:0;    switch(fx)    {        case 0:            if((pan[x-1][y]==trues)&&inside(x-1,y))            {                dfs1(x-1,y,0);                return;            }else            {                dfs2(x,y,0);            }            break;        case 1:            if((pan[x][y-1]==trues)&&inside(x,y-1))            {                dfs1(x,y-1,1);                return;            }else            {                dfs2(x,y,1);            }            break;        case 2:            if((pan[x-1][y-1]==trues)&&inside(x-1,y-1))            {                dfs1(x-1,y-1,2);                return;            }else            {                dfs2(x,y,2);            }            break;        case 3:            if((pan[x-1][y+1]==trues)&&inside(x-1,y+1))            {                dfs1(x-1,y+1,3);                return;            }else            {                dfs2(x,y,3);            }            break;    }}void resetAll(){    for(int i=1;i<16;i++)        for(int j=1;j<16;j++)            pan[i][j]=9;    x=8;    y=8;    isBlack=true;}int main(){    instruction(1);    resetAll();    while(1)    {        char t;        cin>>t;        oldx=x;oldy=y;        if(t=='N')        {                        cin>>x>>y;        }        else if(t=='A')        {            string act;            int num;            cin>>act>>num;            if(act=="R")                y+=num;            if(act=="L")                y-=num;            if(act=="U")                x-=num;            if(act=="D")                x+=num;            if(act=="RU")                x-=num,y+=num;            if(act=="RD")                x+=num,y+=num;            if(act=="LU")                y-=num,x-=num;            if(act=="LD")                y-=num,x+=num;         }        else if(t=='S')        {            print();            continue;        }        else if(t=='?')        {            instruction(2);             continue;         }         else if(t=='i')        {            instruction(3);            continue;         }         else        {            cout<<"未知指令."<<endl;            continue;         }        if((inside(x,y))&&(pan[x][y]==9) )        {            pan[x][y]=(isBlack)?1:0;            clr;            print();            for(int i=0;i<4;i++)            {                nums[i]=0;                dfs1(x,y,i);                if(nums[i]>=5)                {                    string winner=!isBlack?"白棋":"黑棋";                    cout<<winner<<"获得胜利！"<<endl<<"是否重新开始?(输入Y/N)";                    string temp;cin>>temp;                    if(temp=="Y")                     {                        resetAll();                        continue;                    }else{break;}                }            }            isBlack=!isBlack;            continue;        }else        {            cout<<"坐标有误或该处已有棋子。"<<endl;            x=oldx;y=oldy;            continue;        }    }    return 0;}
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