第五章作业

1.调试分析课本每一个例题，有可能的话更改成2-3个方法的新程序；

2.编程实现课本每一个编程习题。

3.编程实现输入两个4X5矩阵和5X3矩阵，定义函数并在主函数中调用计算它们的积。

4.编程计算S[n]=1!+21+3!+...n!。要求定义两个函数，一个计算n!，一个计算s[n]，在后一个函数中调用前一个函数。然后在主程序中输入数n的值，然后调用定义函数输出结果。

5.编写一个函数，输入一个十六进制数，输出相应的十进制数。

书本例题

明哥，书本的例题我只是挑选出对于我来说不懂的题目。。

/******5.6改******/#include <iostream>using namespace std;int max(int u, int v){int w;if(u>v)w = u;elsew = v;return w;}int main(){int a, b, c;cout<<"Please input two numbers: ";cin>>a>>b;c = max(a,b);cout<<"a = "<<a<<"  b = "<<b<<endl;cout<<"Max is "<<c<<endl;return 0;}

/******引用调用******/#include <iostream>using namespace std;void swap(int &u, int &v);int main(){int a = 3;int b = 4;cout<<"a = "<<a<<"  b = "<<b<<endl;swap(a, b);cout<<"a = "<<a<<"  b = "<<b<<endl;return 0;}void swap(int &u, int &v){int temp = v;v = u;u = temp;}

/******sum = 2!+3!******/#include <iostream>using namespace std;long f2(int);long f1(int p){int k;long r;k = p*p;r = f2(k);return r;}long f2(int q){long fact = 1;for(int i = 1;i<=q;i++)fact *= i;return fact;}int main(){int i;long sum = 0;for(i = 2;i <= 3;i++)sum += f1(i);cout<<"sum = "<<sum<<endl;return 0;}

/******弦截法求根5.14******/#include <iostream>#include <cmath>using namespace std;float f(float x);float root(float x1, float x2);float point(float x1, float x2);int main(){float x1, x2, y1, y2, x;do{cout<<"请输入根所在的范围：";cin>>x1>>x2;y1 = f(x1);y2 = f(x2);cout<<"两端点的值为["<<y1<<","<<y2<<"]"<<endl;}while(y1*y2 >= 0);x = root(x1,x2);cout<<"在"<<x1<<"与"<<x2<<"之间，方程的解为"<<x<<endl;return 0;}float f(float x){return(x*x*x-4*x*x+6*x-10);}float root(float x1,float x2){float y1, x, y;y1 = f(x1);do{x = point(x1,x2);y = f(x);if(y*y1>0){y1 = y;x1 = x;}elsex2 = x;}while(fabs(y) >= 0.0001);return x;}float point(float x1, float x2){float y;y = (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));return y;}

/******递归方法求n!******/#include <iostream>using namespace std;float factorial(int n);int main(){int a;float f;cout<<"input an integer number: ";cin>>a;f = factorial(a);cout<<a<<"!="<<f<<endl;return 0;}float factorial(int n){float fact;if(n == 0){fact = 1;}elsefact = n*factorial(n-1);return fact;}

书本习题

书本的习题我还有几道题搞不懂，所以没办法做出来

/******习题2******/#include <iostream>using namespace std;long intPower(int base, int exponent);int main(){int a, n, t;                   //定义变量a和ncout<<"请输入a的值：";cin>>a;cout<<"请输入次幂n的值：";cin>>n;t = intPower(a,n);                      //调用函数求值，把值返回给tcout<<a<<"的"<<n<<"次幂为："<<t<<endl;return 0;}long intPower(int base, int exponent){int i, j = 1;for(i = 0;i<exponent;i++)             //循环求幂{j *= base;}return j;}

/******习题3******/#include <iostream>using namespace std;void number(int x);int main(){int a;char b;while(1){cout<<"请输入正整数a的值：";cin>>a;number(a);cout<<"若继续输入请按Y，若退出请按N。";cin>>b;if(b == 'Y'||b == 'y'){cout<<endl;continue;}else if(b == 'N'||b == 'n')break;}return 0;}void number(int x){int j;for(j=2;j<=x;j++){if(x%j==0){break;}}if(j == x){cout<<x<<"是素数"<<endl<<endl;}else{cout<<x<<"不是素数"<<endl<<endl;}}

/******习题4******/#include <iostream>#include <math.h>                    //库函数的头文件名using namespace std;int change(int x);int main(){int a, i;char b;while(1){cout<<"请输入一个正整数：";cin>>a;i = change(a);cout<<a<<"的顺序相反的整数是 "<<i<<endl<<endl;cout<<"若继续输入请按Y，若退出请按N。";cin>>b;if(b == 'Y'||b == 'y'){cout<<endl;continue;}else if(b == 'N'||b == 'n')break;}return 0;}int change(int x){int i, t, n, k;i = 0, t = x, n = 0;while(t>0){t = t/10;n++;}k = pow(10,n-1);             //这里运用了pow()函数while(x>0){t = x%10;x = x/10;i += t*k;k = k/10;}return i;}

/******习题5******/#include <iostream>using namespace std;void degree(int x);int main(){int a;char b;while(1){cout<<"请输入分数：";cin>>a;degree(a);cout<<"若继续输入请按Y，若退出请按N。";cin>>b;if(b == 'Y'||b == 'y'){cout<<endl;continue;}else if(b == 'N'||b == 'n')break;}return 0;}void degree(int x){switch(x/10){case 6:{cout<<"该学生得D"<<endl<<endl;break;}case 7:{cout<<"该学生得C"<<endl<<endl;break;}case 8:{cout<<"该学生得B"<<endl<<endl;break;}case 9:{cout<<"该学生得A"<<endl<<endl;break;}default:cout<<"该学生Not Pass"<<endl<<endl;}}

/******习题6******/#include <iostream>using namespace std;float ave(int x[10]);int main(){int a[10], i, j;cout<<"请输入10个学生的成绩"<<endl;for(i = 0;i<10;i++){cout<<"a["<<i<<"] = ";cin>>a[i];}j = ave(a);cout<<"这10个学生的平均成绩为："<<j<<endl;return 0;}float ave(int x[10]){int i;float ave = 0;for(i = 0;i<10;i++){ave += x[i];}ave = ave/10;return ave;}

/******习题7******/#include <iostream>using namespace std;int GCD(int a,int b);int LCM(int a,int b);int main(){int num1,num2,gcd,lcm;char j;cout<<"求两个数的最大公约数及最小公倍数"<<endl<<endl;while(1){cout<<"请输入第一个数：";cin>>num1;cout<<"请输入第二个数：";cin>>num2;gcd=GCD(num1,num2);lcm=LCM(num1,num2);                    //输出最大公约数和最小公倍数cout<<"最大公约数为："<<gcd<<endl;cout<<"最小公倍数为："<<lcm<<endl<<endl;cout<<"若继续输入请按Y，若退出请按N。";cin>>j;if(j == 'Y'||j == 'y'){cout<<endl;continue;}else if(j == 'N'||j == 'n')break;}return 0;}int GCD(int a,int b){if ( a % b == 0)return b;elsereturn GCD ( b,a % b) ;}int LCM(int a,int b){int lcm;lcm=a*b/GCD(a,b);           //最小公倍数等于两数之积除以最大公约数return lcm;}

这题要上网查找资料才做得出来

作业3

/******作业3******/#include <iostream>#include <iomanip>using namespace std; int ji(int a[4][5], int b[5][3]);int main() { int a[4][5], b[5][3], c[4][3];int i, j;cout<<"请输入A矩阵："<<endl;for(i = 0;i<4;i++){for(j = 0;j<5;j++){cout<<"a["<<i<<"]"<<"["<<j<<"] = ";cin>>a[i][j];}}cout<<"请输入B矩阵："<<endl;for(i = 0;i<5;i++){for(j = 0;j<3;j++){cout<<"b["<<i<<"]"<<"["<<j<<"] = ";cin>>b[i][j];}}cout<<"A矩阵是："<<endl;for(i = 0;i<4;i++){for(j = 0;j<5;j++){cout<<setw(4)<<a[i][j];}cout<<endl;}cout<<"B矩阵是："<<endl;for(i = 0;i<5;i++){for(j = 0;j<3;j++){cout<<setw(4)<<b[i][j];}cout<<endl;}for(i = 0;i<4;i++)for(j = 0;j<3;j++){c[i][j] = ji(a,b);}cout<<"A矩阵与B矩阵的积为："<<endl;for(i = 0;i<4;i++){for(j = 0;j<3;j++){cout<<setw(4)<<c[i][j];}cout<<endl;}return 0;}int ji(int a[4][5], int b[5][3]){int i, j, k, t;t = 0;for(i = 0;i<5;i++)for(j = 0;j<5;j++){for(k = 0;k<5;k++){t += a[i][k] * b[k][j];}return t;}}

表示最后计算乘积出了点问题，查找不出是哪里出了问题，求明哥解答。。。

作业4

/******作业4******/#include <iostream>using namespace std;float factorial(int n);int main(){int n, i;char b;while(1){float s = 0;cout<<"Please input an integer number: ";cin>>n;for(i = 1;i<=n;i++)s += factorial(i);cout<<"s"<<"["<<n<<"] = "<<s<<endl<<endl;cout<<"若继续输入请按Y，若退出请按N。";cin>>b;if(b == 'Y'||b == 'y'){cout<<endl;continue;}else if(b == 'N'||b == 'n')break;}return 0;}float factorial(int n){float fact;if(n == 0){fact = 1;}elsefact = n*factorial(n-1);return fact;}

作业5

/******作业5******/#include <iostream>using namespace std;void ten(char c[10]);int main(){int i=0;char ch[10];cout<<"请输入一个16进制数:";gets(ch);ten(ch);return 0;}void ten(char c[10]){int value = 0;int i = 0;while (c[i]){if(c[i]>='A'&&c[i]<='F')  value=(c[i]-55)+16*value;        else if(c[i]>='a'&&c[i]<='f')  value=(c[i]-87)+16*value;        else if(c[i]>='0'&&c[i]<='9')  value=(c[i]-48)+16*value;else{cout<<"输入有误"<<endl;break;}i++;}cout<<"十进制数为: "<<value<<endl;}

这题也是上网找资料才做出来的。