【LeetCode】Sort Colors

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Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.

Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.

Note:
You are not suppose to use the library's sort function for this problem.

click to show follow up.

Follow up:
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's.

Could you come up with an one-pass algorithm using only constant space?

思路:主要是分类,就是标定两个符号就是分界点,隔板分开。每次跟1和2比较然后交换顺序得到结果。


class Solution {public:     void sortColors(int A[], int n) {         int i=0;         int flag1=n-1,flag2=n-1;         while(i<=flag1){             if(A[i]==2){                 int tmp=A[i];                 A[i]=A[flag2];                 A[flag2]=tmp;                 flag2--;                 if(flag2<flag1)flag1=flag2;             }else if(A[i]==1){                 int tmp=A[i];                 A[i]=A[flag1];                 A[flag1]=tmp;                 flag1--;             }else{                 i++;             }         }     } };




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