Least Common Multiple

来源:互联网 发布:乐视如何查看mac码 编辑:程序博客网 时间:2024/05/22 15:45

Least Common Multiple

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 17   Accepted Submission(s) : 7
Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
 

Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
 

Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
 

Sample Input
23 5 7 156 4 10296 936 1287 792 1
 

Sample Output
10510296
 
代码如下:

#include <iostream>#include <cstdio>using namespace std;int gcd(int a , int b){    b == 0?a:gcd(b , a%b);}int main(){    int t,n;    scanf("%d",&t);    while(t --)    {        __int64 multi=1;        int first,next;        scanf("%d",&n);        scanf("%d",&first);        multi = first;        for(int i = 1; i < n; i ++)        {            scanf("%d",&next);            multi*= next;            first = gcd(first , next);            first = multi / first;            multi = first;            //cout << first << endl;        }        printf("%d\n",first);    }    return 0;}


0 0
原创粉丝点击