IOS开发之——使用SBJson拼接Json字符串

来源：互联网发布：游戏特效需要什么软件编辑：程序博客网时间：2024/05/01 22:03

SBJson包的下载地址在上一篇文章中。

可以使用NSDictionary中的键值对来拼接Json数据，非常方便，也可以进行嵌套，直接上代码：

    //开始拼接Json字符串    NSDictionary *dataDictionary= [NSDictionary dictionaryWithObjectsAndKeys:@"mac",@"mac",                                   @"game",@"game",                                   @"devicetoken",@"devicetoken",                                   @"device",@"device",                                   @"gv",@"gv",                                   @"lang",@"lang",                                   @"os",@"os",nil];    NSDictionary *parmDictionary= [NSDictionary dictionaryWithObjectsAndKeys:@"getSession",@"act",                                   dataDictionary,@"data",nil];    NSDictionary *jsonDictionary=[NSDictionary dictionaryWithObjectsAndKeys:@"pv",@"pv",                                  parmDictionary,@"param",nil];    SBJsonWriter *writer = [[SBJsonWriter alloc] init];        NSString *jasonString = [writer stringWithObject:jsonDictionary];    NSLog(@"%@",jasonString);

上面的代码用到了三层嵌套，注意的是，NSDictionary中，前面的是值，后面的是键。

拼接后的结果如下：

{"pv":"pv","param":{"act":"getSession","data":{"os":"os","mac":"mac","game":"game","gv":"gv","lang":"lang","devicetoken":"devicetoken","device":"device"}}}

使用Json在线校验工具解析后：

{    "pv": "pv",    "param": {        "act": "getSession",        "data": {            "os": "os",            "mac": "mac",            "game": "game",            "gv": "gv",            "lang": "lang",            "devicetoken": "devicetoken",            "device": "device"        }    }}

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