加密函数中加密的规律是什么？

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#include<stdio.h>#include<string.h>   char string[100];                 char ch,ch1;                          int i,j;   int sum=0;void tongji();void daoxu();void zhuanhuan();void jiami();void lianjie();void tongji(){              printf("请输入你要查找的字母:");           //ch1=getchar();        scanf("%d",&ch1);        ch = getchar();        for(i=0;i<100;i++)        if(string[i]== ch1)        sum++;           printf("總共有%d個%c\n",sum,ch);        }/*void daoxu(){       char string[100];    char ch;    char ch1;      int i,j;    for(j=0;j<i/2;j++)    {        ch1=string[j];        string[j]=string[i-1-j];        string[i-1-j]=ch1;    }    for(i=0;i<100;i++)    printf("%c",string[i]);}void zhuanhuan(){    for(j=0;j<i;j++)    if(string[j]>='a'&&string[j]<='z')    string[j]=string[j-32];    else string[j]=string[j]+32;    for(i=0;i<100;i++)    printf("%c",string[i]);}void jiami(){    printf("請輸入原字符串的內容\n");    scanf("%d",&i);    gets(ch);    encryp(ch,ch1);    puts(ch);    }void lianjie(){     i=0,j=0;    printf("第一个字符串:");    scanf("%s",s1);    printf("第二个字符串:");    scanf("%s",s2);    while (s1[i] !='\0')           i++;    while (s2[j] !='\0')           s1[i++]=s2[j++];             s1[i] ='\0';    printf("连接后: %s\n",s1);}*/void main(){printf("********************欢迎进入字符串管理系统****************\n\n");   int select;   for ( i = 0; i < 100; i++ )          string[i] = ' ';      putwchar('?');    printf("请输入原字符串内容：\n");                      while ( (ch = getchar()) !='\n' )     {      string[i]=ch;                   i++;   }   while(1)    {   printf("**************************************************\n");        printf("*            操 作 选 项                         *\n");        printf("*          1:统计字符串                          *\n");        printf("*          2:倒序字符串                          *\n");        printf("*          3:转换字符串                          *\n");        printf("*          4:加密字符串                          *\n");        printf("*          5:連接字符串                          *\n");        printf("**************************************************\n");        printf("请输入选项(1到5).==>");        scanf("%d",&select);        switch (select)     {         case 1:                  tongji();               break;           /*case 2:               daoxu();               break;         case 3:               zhaunhuan();               break;              case 4:               jiami();               break;             case 5:               lianjie();               break;        */      }    }}
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