ios开发之实现长按UITableViewCell弹出UIMenuController

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项目中需要这个功能，网上找了下资料，有的说得不是很清楚，走了很多弯路才实现了，下面是实现步骤:

1.给cell添加UILongPressGestureRecognizer和相应处理事件

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath

{

..............

UILongPressGestureRecognizer * longPressGesture = [[UILongPressGestureRecognizer alloc]initWithTarget:selfaction:@selector(cellLongPress:)];

[cell addGestureRecognizer:longPressGesture];

return cell;

}

2.配置和显示UIMenuController

- (void)cellLongPress:(UIGestureRecognizer *)recognizer{

if (recognizer.state ==UIGestureRecognizerStateBegan) {

CGPoint location = [recognizerlocationInView:self];

NSIndexPath * indexPath = [selfindexPathForRowAtPoint:location];

UIMyTableViewCell *cell = (UIMyTableViewCell *)recognizer.view;

　　　　　//这里把cell做为第一响应(cell默认是无法成为responder,需要重写canBecomeFirstResponder方法)

[cell becomeFirstResponder];

UIMenuItem *itCopy = [[UIMenuItemalloc]initWithTitle:@"复制"action:@selector(handleCopyCell:)];

UIMenuItem *itDelete = [[UIMenuItemalloc]initWithTitle:@"删除"action:@selector(handleDeleteCell:)];

UIMenuController *menu = [UIMenuControllersharedMenuController];

[menu setMenuItems:[NSArray arrayWithObjects:itCopy, itDelete, nil]];

[menusetTargetRect:cell.frame inView:self];

[menu setMenuVisible:YESanimated:YES];

[itCopy release];

[itDelete release];

}

- (void)handleCopyCell:(id)sender{//复制cell

NSLog(@"handle copy cell");

}

- (void)handleDeleteCell:(id)sender{//删除cell

NSLog(@"handle delete cell");

}

3.在自定义的cell里重写canBecomeFirstResponder方法，返回yes

//为了让菜单显示，目标视图必须在responder链中，很多UIKit视图默认并无法成为一个responder，因此你需要使这些视图重载 canBecomeFirstResponder方法，并返回YES

- (BOOL)canBecomeFirstResponder{

return YES;

}

经过这几步，就可以成功显示了，又在网上看到一篇讲这个的外文，分享一下：

http://www.intridea.com/blog/2010/12/22/developers-notes-for-uimenucontroller

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