codeforces 427B

http://codeforces.com/problemset/problem/427/B

The prison of your city has n prisoners. As the prison can't accommodate all of them, the city mayor has decided to transfer c of the prisoners to a prison located in another city.

For this reason, he made the n prisoners to stand in a line, with a number written on their chests. The number is the severity of the crime he/she has committed. The greater the number, the more severe his/her crime was.

Then, the mayor told you to choose the c prisoners, who will be transferred to the other prison. He also imposed two conditions. They are,

• The chosen c prisoners has to form a contiguous segment of prisoners.
• Any of the chosen prisoner's crime level should not be greater then t. Because, that will make the prisoner a severe criminal and the mayor doesn't want to take the risk of his running away during the transfer.

Find the number of ways you can choose the c prisoners.

Input

The first line of input will contain three space separated integers n (1 ≤ n ≤ 2·105), t (0 ≤ t ≤ 109) andc (1 ≤ c ≤ n). The next line will contain n space separated integers, the ith integer is the severity ithprisoner's crime. The value of crime severities will be non-negative and will not exceed 109.

Output

Print a single integer — the number of ways you can choose the c prisoners.

Sample test(s)

input

4 3 32 3 1 1

output

2

input

1 1 12

output

0

input

11 4 22 2 0 7 3 2 2 4 9 1 4

output

6

#include <stdio.h>#include <string.h>#include <iostream>using namespace std;int main(){    int n,c,t,x;    while(~scanf("%d%d%d",&n,&t,&c))    {        int sum=0;        int count=0;        int flag=1;        for(int i=0;i<n;i++)        {            scanf("%d",&x);            if(x<=t)                sum++;            else            {                flag=0;                if(sum>=c)                    count+=sum-c+1;                sum=0;            }            //printf("(%d,%d,%d)\n",i,sum,count);        }        if(flag&&sum>=c)        {            count+=sum-c+1;        }        else if(sum>=c)        {            count+=sum-c+1;        }        printf("%d\n",count);    }    return 0;}