Aizu 1315 Gift from the Goddess of Programming

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题目链接:Aizu 1315 Gift from the Goddess of Programming

我是一个一个人模拟的,以为会超时,没想到0ms。。

可能有更好的办法吧。

#include <iostream>#include <cstring>#include <cstdio>using namespace std;const int MAX_N = 1000 + 10;struct S{    int id, time;    char str[3];};int n;S s[MAX_N];int in_time;int main(){    while(scanf("%d", &n), n)    {        int y, m, h, mm, id, max_id = 0;        char str[3];        for(int i = 0; i < n; i++)        {            scanf("%d/%d %d:%d %s %d", &y, &m, &h, &mm, str, &id);            s[i].id = id, s[i].time = h * 60 + mm, strcpy(s[i].str, str);            max_id = max(max_id, id);        }        bool is_at1, is_at2;        is_at1 = is_at2 = false;        int _beg_time, temp_time, max_time;        max_time = temp_time = 0;        _beg_time =  -1;        for(int j = 1; j <= max_id; j++)        {            for(int i = 0; i < n; i++)            {                if(s[i].id == 0)                {                    if(s[i].str[0] == 'I')                    {                        is_at1 = true;                        if(is_at2 == true)                            _beg_time = s[i].time;                    }                    else                    {                        is_at1 = false;                        if(is_at2 == true)                        {                            if(_beg_time != -1)                            {                                temp_time += s[i].time - _beg_time;                                _beg_time = -1;                            }                        }                    }                }                else                {                    if(s[i].id == j)                    {                        if(s[i].str[0] == 'I')                        {                            is_at2 = true;                            if(is_at1 == true)                                _beg_time = s[i].time;                        }                        else                        {                            is_at2 = false;                            if(_beg_time != -1)                            {                                temp_time += s[i].time - _beg_time;                                 _beg_time = -1;                            }                        }                    }                }           }           max_time = max(max_time, temp_time);           _beg_time = -1;           temp_time = 0;        }        printf("%d\n", max_time);    }    return 0;}


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