UVaOJ 445 Marvelous Mazes

445-Marvelous Mazes

our mission, if you decide to accept it, is to create a mazedrawing program. A maze will consist of the alphabeticcharactersA-Z,* (asterisk), and spaces.Input and Output

Your program will getthe information for the mazes from the input file. This filewill contain lines of characters which your program mustinterpret to draw a maze. Each row of the maze will be describedby a series of numbers and characters, where the numbers before acharacter tell how many times that character will be used. Ifthere are multiple digits in a number before a character, thenthe number of times to repeat the character is the sum of thedigits before that character.

The lowercase letter "b" will beused in the input file to represent spaces in the maze. Thedescriptions for different rows in the maze will be separated byan exclamation point (!) or by an end of line.

Descriptions fordifferent mazes will be separated by a blank line in both input and output. The inputfile will be terminated by an end of file.

There is no limit tothe number of rows in a maze or the number of mazes in a file,though no row will contain more than 132 characters.

Happy mazing!

Sample Input

1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X4X1b1X

Sample Output

T TTTTTT  T TTT T  TTT   T TTTT   TT   T TTTTTT*T XX   XXXXX X这道题大意就是将输入的字符串翻译为图像，b代表空格，！代表换行（\n），数字代表每个字符的个数C++和C比较混乱。。
#include <iostream>#include <cstdio>using namespace std;int main(){int  sum = 0;char c;while ((c = getchar()) != EOF){if (c>='0' && c<='9'){sum = sum + c - 48;continue;}else if (c == '!' || c == '\n'){putchar('\n');}        else{for (int x = 0; x<sum; x++){if(c=='b')                    cout<<' ';                else                    cout<<c;}sum = 0;}}        return 0;}