codeforce 5B Center Alignment

B. Center Alignment

time limit per test

1 second

memory limit per test

64 megabytes

input

standard input

output

standard output

Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.

You are to implement the alignment in the shortest possible time. Good luck!

Input

The input file consists of one or more lines, each of the lines contains Latin letters, digits and/or spaces. The lines cannot start or end with a space. It is guaranteed that at least one of the lines has positive length. The length of each line and the total amount of the lines do not exceed 1000.

Output

Format the given text, aligning it center. Frame the whole text with characters «*» of the minimum size. If a line cannot be aligned perfectly (for example, the line has even length, while the width of the block is uneven), you should place such lines rounding down the distance to the left or to the right edge and bringing them closer left or right alternatively (you should start with bringing left). Study the sample tests carefully to understand the output format better.

题目大意是给一些字符串，然后依次将他们居中打印出来。然后用一个最小的星星围成的矩形把这些包围起来。当不能恰好居中的时候比较麻烦，需要先中靠左输出，下次遇到不能恰好居中的就中偏右输出，交替进行。我会告诉你我这题交了7次么，瞎了。

#include <iostream>#include <cstdio>#include <cstdlib>#include <cmath>#include <cstring>#include <string>#include <stack>#include <map>#include <queue>#include <algorithm>using namespace std;void putc(int n, char c) {    while (n--) cout << c;}int main() {    string str[1005];    char ctmp[1005];    int cnt = 0;    int longest = 0;    while (cin.getline(ctmp, 1005)) {        str[cnt] = ctmp;        if (str[cnt].length() > longest) longest = str[cnt].length();        cnt ++;    }    int err = 0;    int left, right;    putc(longest+2, '*');    cout << endl;    for (int i = 0; i < cnt; i++) {        left = (longest - str[i].length()) / 2;        right = longest - left - str[i].length();        if (left != right) {            left += (err % 2 == 0 ? 0 : 1);            right -= (err % 2 == 0 ? 0 : 1);            err++;        }        cout << '*';        putc(left, ' ');        cout << str[i];        putc(right, ' ');        cout << '*' << endl;    }    putc(longest+2, '*');    cout << endl;    return 0;}