C语言交换两个数的值

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先来看一段C语言的代码

#include <stdio.h>void swap(int x,int y){int temp;temp = x;x = y;y = temp;printf("In swap: x = %d,y = %d\n",x,y);}void swap_with_pt(int * x,int * y){int temp;temp = *x;*x = *y;*y = temp;printf("In swap_with_pt: x = %d,y = %d\n",*x,*y);}int main(){int x = 5,y = 10;printf("Before swap: x = %d,y = %d\n",x,y);swap(x,y);printf("After swap: x = %d,y = %d\n",x,y);printf("-------------------------------\n");printf("Before swap_with_pt: x = %d,y = %d\n",x,y);swap_with_pt(&x,&y);printf("After swap_with_pt: x = %d,y = %d\n",x,y);return 0;}

输出如下:

Before swap: x = 5,y = 10In swap: x = 10,y = 5After swap: x = 5,y = 10---------------------------------Before swap_with_pt: x = 5,y = 10In swap_with_pt: x =10,y = 5After swap_with_pt: x = 10,y = 5

解释:

      swap函数调用时首先创建x,y的变量副本,我们姑且称之为x2,y2(其实名字依然是x和y,只不过这里的x和y只在swap函数里有意义),并将main函数中x,y的值传给变量x2,y2,然后函数交换了x2,y2的值,运行完函数后x2,y2变量生命期结束。所以,x和y的值是不变的。

      swap_with_pt函数调用时同样创建x,y的指针的变量副本,我们姑且称之为x2,y2(其实名字依然是x和y,只不过这里的x和y只在swap_with_pt函数里有意义),并将x,y的地址值传给x2,y2,这个时候x2和y2是指向main函数中x,y的,然后通过*运算修改x,y的值。注意,“*+指针名”是可以改变它所指向的变量的值的。





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