HDU 1048 What Is Your Grade? (简单模拟)

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                                           What Is Your Grade?

Problem Description
“Point, point, life of student!”
This is a ballad(歌谣)well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this course.
There are 5 problems in this final exam. And I will give you 100 points if you can solve all 5 problems; of course, it is fairly difficulty for many of you. If you can solve 4 problems, you can also get a high score 95 or 90 (you can get the former(前者) only when your rank is in the first half of all students who solve 4 problems). Analogically(以此类推), you can get 85、80、75、70、65、60. But you will not pass this exam if you solve nothing problem, and I will mark your score with 50.
Note, only 1 student will get the score 95 when 3 students have solved 4 problems.
I wish you all can pass the exam!
Come on!
 

Input
Input contains multiple test cases. Each test case contains an integer N (1<=N<=100, the number of students) in a line first, and then N lines follow. Each line contains P (0<=P<=5 number of problems that have been solved) and T(consumed time). You can assume that all data are different when 0<p.
A test case starting with a negative integer terminates the input and this test case should not to be processed.
 

Output
Output the scores of N students in N lines for each case, and there is a blank line after each case.
 

Sample Input
45 06:30:174 07:31:274 08:12:124 05:23:1315 06:30:17-1
 

Sample Output
100909095100
 

Author
lcy
 

源代码:
#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>#define maxn 110using namespace std;int sum[10];struct people{    int pro;   //问题数    int sco;   //分数    char time[20];    int pos;    //原来的位置}p[maxn];bool cmp1(people a,people b){    if(a.pro==b.pro)        return strcmp(b.time,a.time)>0?1:0;            //注意这里,,,让我WA爆了,,,,非0,都是真!!!<img alt="哭" src="http://static.blog.csdn.net/xheditor/xheditor_emot/default/cry.gif" />    else        return a.pro>b.pro;}bool cmp2(people a,people b){    return a.pos<b.pos;}int main(){    int t;    while(scanf("%d",&t),t!=-1)     //数据输入    {        memset(sum,0,sizeof sum);        for(int i=0;i<t;i++)        {            scanf("%d%s",&p[i].pro,p[i].time);            sum[p[i].pro]++;        //计数,一个问题数,,的个数            p[i].pos=i;        }        for(int i=1;i<=4;i++)       //前一半,数            if(sum[i]!=1)                sum[i]=sum[i]/2;        sort(p,p+t,cmp1);           //问题数,大到小,时间少到多        for(int i=0;i<t;i++)        {            if(p[i].pro==5)        //5个                p[i].sco=100;            else            {                if(p[i].pro==0)    //0个                    p[i].sco=50;                else         //1~4个                {                    if(sum[p[i].pro]>0)                    {                        p[i].sco=p[i].pro*10+55;   //用一个前一半,                        sum[p[i].pro]--;           //减一个                    }                    else                        p[i].sco=p[i].pro*10+50;                }            }        }        sort(p,p+t,cmp2);              //按pos位置,复原        for(int i=0;i<t;i++)            printf("%d\n",p[i].sco);        printf("\n");    }    return 0;}


(坑啊。。。。trcmp()函数用错了。。。。。WA爆了)
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