LeetCode OJ - Candy

来源:互联网 发布:《优化重组卷》数学 编辑:程序博客网 时间:2024/06/07 07:12

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

貌似很多题都是两边扫描啊,或者多编

int candy(vector<int> &ratings) {    if(ratings.empty()) return 0;    vector<int> candy(ratings.size(), 1);    for(int i = 0; i < ratings.size() - 1; i++) {        if(ratings[i] < ratings[i + 1])  candy[i + 1] = candy[i] + 1;    }    for(int i = ratings.size() - 2; i > 0; i--) {        if(ratings[i] > ratings[i + 1] && candy[i] < candy[i + 1] + 1)            candy[i] = candy[i + 1] + 1;       }    int ret = 0;    for(int i = 0; i < candy.size(); i++) {        ret += candy[i];    }    return ret;}



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