第二学期第13周项目1--点、圆的关系

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/* * Copyright (c) 2013, 烟台大学计算机学院 * All rights reserved. * 作    者：  沈远宏 * 完成日期：2014 年 05月20日 * 版 本 号：v1.0 * 问题描述：（1）先建立一个Point(点)类，包含数据成员x,y(坐标点)；             （2）以Point为基类，派生出一个Circle(圆)类，增加数据成员(半径)，基类的成员表示圆心；             （3）编写上述两类中的构造、析构函数及必要运算符重载函数（本项目主要是输入输出）；             （4）定义友元函数int locate，判断点p与圆的位置关系（返回值<0圆内，==0圆上，>0 圆外）； * 输出：*/#include <iostream>#include <cmath>using namespace std;class Point{protected:    double x;    double y;public:    Point(double xx=0,double yy=0):x(xx),y(yy) {}    ~Point()    {        cout<<"已释放Point\n";    }    friend istream& operator >>(istream& in,Point &p);    friend ostream& operator <<(ostream& out,Point &p);    double getx()    {        return x;    }    double gety()    {        return y;    }};istream& operator >>(istream& in,Point &p){    in>>p.x>>p.y;    return  in;}ostream& operator <<(ostream& out,Point &p){    out<<"("<<p.x<<","<<p.y<<")";    return  out;}class Circle: public Point{protected:    double r;public:    Circle(double xx,double yy,double rr):Point(xx,yy),r(rr) {}    ~Circle()    {        cout<<"已释放Circle\n";    }    friend istream& operator >>(istream& in,Circle &c);    friend ostream& operator <<(ostream& out,Circle &c);    friend double locate(Point p,Circle c);};istream& operator >>(istream& in,Circle &c){    in>>c.x>>c.y>>c.r;    return in;}ostream& operator <<(ostream& out,Circle &c){    out<<"该圆为以"<<"("<<c.x<<","<<c.y<<")"<<"为圆心，以"<<c.r<<"为半径的"<<endl;    return out;}double locate(Point p,Circle c){    double distance;    distance=sqrt((p.getx()-c.x)*(p.getx()-c.x)+(p.gety()-c.y)*(p.gety()-c.y));    return (distance-c.r);}int main( ){    Circle c1(3,2,4),c2(4,5,5);      //c2应该大于c1    Point p1(1,1),p2(3,-2),p3(7,3);  //分别位于c1内、上、外    cout<<"圆c1: "<<c1;    cout<<"点p1: "<<p1;    cout<<"点p1在圆c1之"<<((locate(p1, c1)>0)?"外":((locate(p1, c1)<0)?"内":"上"))<<endl;    cout<<"点p2: "<<p2;    cout<<"点p2在圆c1之"<<((locate(p2, c1)>0)?"外":((locate(p2, c1)<0)?"内":"上"))<<endl;    cout<<"点p3: "<<p3;    cout<<"点p3在圆c1之"<<((locate(p3, c1)>0)?"外":((locate(p3, c1)<0)?"内":"上"))<<endl;    return 0;}
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