【POJ】1004 Financial Management

Description

Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

Input

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

Output

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

Sample Input

100.00489.1212454.121234.10823.05109.205.271542.25839.1883.991295.011.75

Sample Output

$1581.42

水题一枚。求12个月所剩余额的平均数。

但是好像有陷阱？不知道耶。

毕竟我没水过去...

这是我WA无数遍的代码，有大神吗求指教。

#include<stdio.h>#include<iostream>using namespace std;int main(){    double money=0.0;    for(int i=0;i<12;i++)    {        double sum;        scanf("%lf",&sum);        money+=sum;    }    printf("$%.2lf\n",money/12.0);    return 0;}

小優YoU

下面是小優YoU的AC代码：

来自 優YoUhttp://blog.csdn.net/lyy289065406/article/details/6642577

#include<iostream>#include<iomanip>using namespace std;int main(void){double sum=0.0;for(int i=1;i<=12;i++){double temp;cin>>temp;sum+=temp;}cout<<fixed<<setprecision(2)<<'$'<<sum/12.0<<endl;return 0;}