对象转换

Problem F: C++习题 对象转换

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Description

定义一个Teacher(教师)类（教师号，姓名，性别，薪金）和一个Student(学生)类（学号，姓名，性别，成绩），二者有一部分数据成员是相同的，num(号码)，name(姓名),sex(性别)。编写程序，将一个Student对象(学生)转换为Teacher(教师)类，只将以上3个相同的数据成员移植过去。可以设想为： 一位学生大学毕业了，留校担任教师，他原有的部分数据对现在的教师身份来说仍然是有用的，应当保留并成为其教师数据的一部分。

Input

一个教师的信息和一个学生的信息

Output

学生的信息和学生转换为教师后的信息

Sample Input

10001 Li f 1234.520010 Wang m 89.5

Sample Output

student1:

num:20010

name:Wang

sex:m

score:89.50

teacher2:

num:20010

name:Wang

sex:m

pay:1500.00

HINT

#include <iostream>#include <iomanip>#include <string.h>#include <cstdio>using namespace std;class Student{public:    Student(int,char[],char,float);    int get_num(){return num;}    char *get_name(){return name;}    char get_sex(){return sex;}    void display()    {        cout<<"num:"<<num<<"\nname:"<<name<<"\nsex:"<<            sex<<"\nscore:"<<score<<"\n";    }private:    int num;    char name[20];    char sex;    float score;};Student::Student(int n,char nam[],char s,float sco){    num=n;    strcpy(name,nam);    sex=s;    score=sco;}class Teacher{public:    Teacher(){}    Teacher(Student &);    Teacher(int n,char nam[],char sex,float pay);    float setpay(float ){return pay;}    void display();private:    int num;    char name[20];    char sex;    float pay;};Teacher::Teacher(int n,char nam[],char s,float p){    num=n;    strcpy(name,nam);    sex=s;    pay=p;}Teacher::Teacher(Student &stud){    num=stud.get_num();    strcpy(name,stud.get_name());    sex=stud.get_sex();    pay=1500;}void Teacher::display(){    cout<<"num:"<<num<<"\nname:"<<name<<"\nsex:"<<        sex<<"\npay:"<<pay<<"\n";} int main(){    cout<<setiosflags(ios::fixed);    cout<<setprecision(2);    int num;    char name[20];    char sex;    float score;    float pay;    cin>>num>>name>>sex>>pay;    Teacher teacher1(num,name,sex,pay);    cin>>num>>name>>sex>>score;    Student student1(num,name,sex,score);    cout<<"student1:"<<endl;    student1.display();    Teacher teacher2=Teacher(student1);    teacher2.setpay(1500);    cout<<"teacher2:"<<endl;    teacher2.display();    return 0;}