7_leetcode_container with most water

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Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

//1:考虑特殊情况,2:前后两个指针,算出两个指针之间的水量; 3:当前指向的水少的指针向另外一个指针靠近

    int maxArea(vector<int> &height)    {        if(height.size() <= 1)            return 0;                int water = 0;                int left = 0;        int right = (int)height.size() - 1;                while(left < right)        {            int distance = right - left;            int temp = (height[left] > height[right] ? height[right] : height[left]);                        if(temp * distance > water)            {                water = temp * distance;            }                        if(height[left] < height[right])            {                left++;            }            else            {                right--;            }        }                return water;    }


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