HDU 1075 What Are You Talking About

Problem Description

Ignatius is so lucky that he met a Martian yesterday. But he didn't know the language the Martians use. The Martian gives him a history book of Mars and a dictionary when it leaves. Now Ignatius want to translate the history book into English. Can you help him?

 

Input

The problem has only one test case, the test case consists of two parts, the dictionary part and the book part. The dictionary part starts with a single line contains a string "START", this string should be ignored, then some lines follow, each line contains two strings, the first one is a word in English, the second one is the corresponding word in Martian's language. A line with a single string "END" indicates the end of the directory part, and this string should be ignored. The book part starts with a single line contains a string "START", this string should be ignored, then an article written in Martian's language. You should translate the article into English with the dictionary. If you find the word in the dictionary you should translate it and write the new word into your translation, if you can't find the word in the dictionary you do not have to translate it, and just copy the old word to your translation. Space(' '), tab('\t'), enter('\n') and all the punctuation should not be translated. A line with a single string "END" indicates the end of the book part, and that's also the end of the input. All the words are in the lowercase, and each word will contain at most 10 characters, and each line will contain at most 3000 characters.

 

Output

In this problem, you have to output the translation of the history book.

 

Sample Input

STARTfrom fiwohello difhmars riwosfearth fnnvklike fiiwjENDSTARTdifh, i'm fiwo riwosf.i fiiwj fnnvk!END

 

Sample Output

hello, i'm from mars.i like earth!

题目大意就是翻译文章，从火星文翻译成英文 - - || ，字典里没有的，标点及空格之类的 照火星文原样输出。字典里有的按翻译后输出。

我的解决办法是 用一个数组记录每一个火星单词对应的英文单词，查找时如果找到就返回已经保存下来的英文单词。

注意数组要开大。。RE了好多次。

#include<stdio.h>#include<string.h>int ch[7001000][26];char cun[7001000][31];  //记录已经存在于字典里的词组int val[7001000] ,sz=1;char sss[7];char a[31] , b[31] ,ju[3005];int id(char x) {return x-'a';}void Inse(char *s ){    int u=0;    for(int i=0;s[i];i++) {        int c=id(s[i]);        if(!ch[u][c]) ch[u][c]=sz++;        u=ch[u][c];    }    val[u]=1;    strcpy(cun[u],a);}int Find(char *s){    int u=0;    for(int i=0;s[i];i++) {        int c=id(s[i]);        if(!ch[u][c]) return -1;        u=ch[u][c];    }    if(val[u] == 1) return u;    else return -1;}char s[11];int main() {    scanf("%s",sss); getchar();    while(1) {        scanf("%s",a);        if(a[0] == 'E') break;        scanf("%s",b); getchar();        Inse(b);    }    scanf("%s",sss); getchar();    while(1) {        gets(ju);        if(ju[0] == 'E')            break;        int k=0;        for(int i=0; ju[i] ;i++) {            if(ju[i]>='a' && ju[i] <= 'z') {                s[k++]=ju[i];            } else if(s[0] != 0){  //如果s里有火星文单词，就去找有没有对应的英文单词                int u=Find(s);                if(u!=-1) printf("%s",cun[u]);                else printf("%s",s);                printf("%c",ju[i]);                memset(s,0,sizeof(s));                k=0;            }            else printf("%c",ju[i]); //如果不是字母且s里没有单词，那么这个字符就可能是标点或空格，直接输出        }        printf("\n");    }    return 0;}