LeetCode 18. Letter Combinations of a Phone Number
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依题意做即可，输入为2-9间的数字。
代码：
class Solution {public: vector<string> letterCombinations(string digits) { vector<string> ret(1, ""); string letters[] = {"abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; for (size_t i = 0; i < digits.size(); ++ i) { string str = letters[digits[i]-'2']; for (int j = ret.size()-1; j >= 0; -- j) { for (int k = str.size()-1; k >= 0; -- k) { if (k != 0) { ret.push_back( ret[j] + str[k] ); } else { ret[j] += str[k]; } } } } return ret; }}; 0 0
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