NOJ [1263] All Kill

• 问题描述
• Now is the Z country's extraordinary period,Ning x City broke out in a procession, the relevant departments accidentally get some data, by analysis, 
  this is M country' ciphertext. . . Now, we get the correct way to decryption .
  Now,you have to do it, for each of the ciphertext, presence a number x of corresponding , represents the originaltext. moved to the right of the x-bit to get 
  ciphertext, and now output correct the original.If you donn't,you will be kill !!!
  

  
  
• 输入
• This problem contains several cases.
  The first line of each case is the ciphertext(the length < 100000).
  The next line is the number,that is every ciphertext'x.
  
• 输出
• printf the originaltext. You have to leave a blank line between each two cases.
  
  
  
  
  一开始把Case写成了CASE。。。。。。大家不要犯这种低级错误啊
  
  
  
  

  #include<stdio.h>#include<string.h>char ciphertext[100010];char number_x[100010];char originaltext[100010];int main(){int p=1;while(~scanf("%s",ciphertext)){scanf("%s",number_x);int len=strlen(ciphertext),i;for(i=0;i<len;i++){if(ciphertext[i]>='a' && ciphertext[i]<='z')//小写字母{char c=ciphertext[i]-'a'-(number_x[i]-'0')+'a';if(c>='a')  originaltext[i]=c;        else          originaltext[i]='z'-('a'-c)+1;} else if(ciphertext[i]>='A' && ciphertext[i]<='Z'){char c=ciphertext[i]-'A'-(number_x[i]-'0')+'A';if(c>='A')  originaltext[i]=c;        else          originaltext[i]='Z'-('A'-c)+1;}}originaltext[len]='\0';if(p>1)  printf("\n");       printf("Case %d: %s\n",p,originaltext);p++;}return 0;}