LeetCode 22. Merge k Sorted Lists
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用一个最小堆盛放所有有序链表的头结点即可。
复杂度O(nlogm) -- n为结点总数，m为vector.size()
代码：
class Solution {public:struct cmp{bool operator () (const ListNode* a, const ListNode* b){return a->val > b->val;}};ListNode *mergeKLists(vector<ListNode *> &lists) {ListNode *head=NULL, *cur=NULL;priority_queue<ListNode*, vector<ListNode*>, cmp> ss;for (auto it = lists.begin(); it != lists.end(); ++ it){if (*it != NULL){ss.push(*it);}}while(ss.empty() == false){auto top = ss.top();if (head == NULL){head = cur = top;} else{cur->next = top;cur = cur->next;}ss.pop();if (top->next != NULL){ss.push(top->next);}}return head;}}; 0 0
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