虚函数练习：交通工具信息

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Problem E: 交通工具信息

Description

有一个交通工具类vehicle，将它为基类派生的有派生小车类car，卡车类truck和轮船类boat，定义这些类，并使其能够显示其各类交通工具的详细信息。

他们包含的信息，有如下几种：

1.名字 -----与输入的名字相符合

2.时速(km/h) -----最高时速

3.耗油量(L/100km) -----在经济时速下测得耗油量

小车类：
250km/h
14.8 L/100km
卡车类：
140km/h
18L/100km
轮船类：
50km/h
8.33L/100km

Input

输入三个派生类对应名字。

Output

输出对应类型的信息。

Sample Input

Mercedes_BenzTransport_truckBoat

Sample Output

Mercedes_Benz250km/h14.8L/100kmTransport_truck140km/h18L/100kmBoat50km/h8.33L/100km

HINT

#include <iostream> #include <string>using namespace std; class Vehicle { public:    string name ;   public:     Vehicle (string h): name(h){} virtual void showinfo () const{cout<<name<<endl; }}; class Car :virtual public Vehicle    { public: double Speed;       double fuel ;  public:       Car (string h): Vehicle (h),Speed(250),fuel(14.8){} virtual void showinfo () const{cout<<name<<endl;         cout<<Speed<<"km/h"<<endl;         cout<<fuel<<"L/100km"<<endl; }};class Truck :virtual public Vehicle   { public:      double Speed;       double fuel ;  public:       Truck (string h): Vehicle (h),Speed(140),fuel(18){} virtual void showinfo () const{cout<<name<<endl;         cout<<Speed<<"km/h"<<endl;         cout<<fuel<<"L/100km"<<endl; }};class Boat :virtual public Vehicle    { public:    double Speed;       double fuel ;   public:       Boat (string h): Vehicle (h),Speed(50),fuel(8.33){} virtual void showinfo () const{cout<<name<<endl;         cout<<Speed<<"km/h"<<endl;         cout<<fuel<<"L/100km"<<endl; }};int main(){    Vehicle *vp;    string name0,name1,name2;    cin>>name0;    Car car(name0);    cin>>name1;    Truck truck(name1);    cin>>name2;    Boat boat(name2);    vp=&car;    vp->showinfo ();    vp=&truck;    vp->showinfo ();    vp=&boat;    vp->showinfo ();    return 0;}

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