IOS应用开发02——视图跳转

来源：互联网发布：mac系统照片图库打不开编辑：程序博客网时间：2024/06/05 02:09

1.代码控制storyboard中的Segue跳转

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{    if ([segue.identifier isEqualToString:@"pushDetailView"])    {        // 点击cell就会转向详细页面.        NSArray *sourceArray;        NSIndexPath *indexPath = [self.searchDisplayController.searchResultsTableView                                  indexPathForCell:(UITableViewCell *)sender];        if (indexPath != nil){            sourceArray = self.searchResults;        }        else{            indexPath = [self.tableView indexPathForCell:(UITableViewCell *)sender];            sourceArray = self.records;        }                // 得到详细视图控制器        TZRecordDetailViewController *destinationController = segue.destinationViewController;        TZRecord *record = sourceArray[indexPath.row];        destinationController.title = record.name;        destinationController.record = record;        // 设置信息，并传数据过去            }}

2.从storyboard中得到一个ViewController方法

 /*  -----------------从storyboard中得到视图控制器，并且初始化数据，设置信息--------------  */    UIStoryboard* storyboard = [UIStoryboard storyboardWithName:@"Main_iPhone" bundle:nil];    //得到名为aaa的VC实例 也就是说在storyboard中设置的VC其实是你已链接类的一个实例    TZFriendsViewController *friendsViewController = [storyboard instantiateViewControllerWithIdentifier:@"TZFriendsViewController"];    friendsViewController.records = recordArray;    // 定义recordArray数组赋值给friendsViewController    friendsViewController.title = @"好友";    friendsViewController.tabBarItem.image = [UIImage imageNamed:@"friends"];    // 设置标题及图片

3.navigationcontroller 弹出视图方法

[self.navigationController popViewControllerAnimated:YES];// 弹出当前视图控制器,显示前一视图[self.navigationController popToViewController:viewController animated:YES];// 弹出到指定视图控制器[self.navigationController popToRootViewControllerAnimated:YES];// 弹出到根视图控制器setNavigationBarHidden:BOOL animated:BOOL;// 设置导航控制器状态

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