leetcode:Reverse Integer
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翻转数字
public class Solution { public int reverse(int x) { boolean flag = x < 0; ArrayList<Integer> sta = new ArrayList<>(); x = Math.abs(x); while(x != 0){ sta.add(x % 10); x /= 10; } for(int i = 0; i < sta.size(); ++i){ x *= 10; x += sta.get(i); } return flag ? -x : x; }}
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