杭电1002 A+B problem II

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A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 203978 Accepted Submission(s): 39201

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

21 2112233445566778899 998877665544332211

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110import java.util.Scanner;import java.math.BigInteger;public class Main {    public static void main(String[] args) {        // TODO Auto-generated method stub        Scanner cin=new Scanner (System.in);        int n;        int d=0;        n=cin.nextInt();        while(n-->0){            d++;                        BigInteger a=cin.nextBigInteger();            BigInteger b=cin.nextBigInteger();            System.out.println("Case "+d+":");            BigInteger c=a.add(b);            System.out.println(a+" + "+b+" = "+c);            if(n!=0)System.out.println("");        }            }}

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