LeetCode:Length of Last Word
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分析:
用个变量last保存遍历到当前位置的最后一个空格位置,只要当前字符不是空格,就更新res,这样下来,最终res里面存放的就是所要求的结果.需要注意的是,last变量的初值.
解题代码:
class Solution {public: int lengthOfLastWord(const char *s) { if (s == NULL) return 0; int res = 0,last = -1; for (int i = 0; s[i]; ++i) { if( s[i] == ' ') { last = i; continue; } res = i - last; } return res; }};
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