从1输出n位数字

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#include <iostream>#include <cstdio>using namespace std;int IsEnd(int *number,int len){     if(number==NULL || len<=0) return NULL;    for(int i=0;i<len;i++)        if(number[i]!=9)        return 0;    return 1;}int *numberAdd1(int *number,int len){    if(number==NULL || len<=0) return NULL;    int jinwei=1;    for(int i=len-1;i>=0;i--)    {        int one=number[i]+jinwei;        number[i]=one%10;        jinwei=one/10;    }    /*for(int i=0;i<len;i++)        printf("%d",number[i]);    printf("\n");*/    return number;}void PrintNum(int *number,int len){    if(number==NULL || len<=0) return ;    int i=0;    while(number[i]==0)        i++;    for(;i<len;i++)        printf("%d",number[i]);    printf("\n");}int main(){    int number[]={0,0,0,0,0};    int *number1=number;    while(!IsEnd(number1,5))    {        number1=numberAdd1(number1,5);        PrintNum(number1,5);    }    return 0;}

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