pushlet服务端推送——点对点单播(不用修改lib包)

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pushlet点对点单播,在网上看 ,大家都是将包修改然后替换lib中class,其实不用不这么麻烦,java可以继承嘛,继承原来的类重写里面的方法就行,不必编译出来替换class,这样不方便修改

 

新建一个类,继承nl.justobjects.pushlet.core.SessionManager类,重写里面的createSession方法即可

package com.pushlet.serveToClient;import javax.servlet.http.HttpSession;import org.apache.struts2.ServletActionContext;import nl.justobjects.pushlet.core.Event;import nl.justobjects.pushlet.core.Session;import nl.justobjects.pushlet.core.SessionManager;import nl.justobjects.pushlet.util.PushletException;public class MySessionManager extends SessionManager {@Overridepublic Session createSession(Event anEvent) throws PushletException {// TODO Auto-generated method stubHttpSession s = ServletActionContext.getRequest().getSession();String userid=s.getAttribute("userid")+"";return Session.create(userid);}}


 

然后修改配置pushlet.properties这个配置文件

 

 

然后调用方法推送

   Event event =Event.createDataEvent("/mutiSend");
   event.setField("msg", URLEncoder.encode(remindContent+"<br/>推送时间:"+new Date().toLocaleString(),"UTF-8"));
   Dispatcher.getInstance().unicast(event, "muyunfei");

 

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