LeetCode 105 Construct Binary Tree from Preorder and Inorder Traversal
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Given preorder and inorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
思路：递归
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution {public TreeNode buildTree(int[] preorder, int[] inorder) {return buildTree(preorder, 0,preorder.length-1,inorder,0,inorder.length-1);}public TreeNode buildTree(int[] preorder, int s1,int e1,int[] inorder,int s2,int e2) {if(s1<=e1&&s2<=e2){TreeNode temp=new TreeNode(preorder[s1]);int i=s2;for(;i<=e2&&inorder[i]!=preorder[s1];i++);temp.left=buildTree(preorder,s1+1,s1+i-s2,inorder,s2,i-1);temp.right=buildTree(preorder,s1+i-s2+1,e1,inorder,i+1,e2);return temp;}else return null;}} 0 0
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