poj3664Election Time

Election Time

Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 7224 Accepted: 3920

Description

The cows are having their first election after overthrowing the tyrannical Farmer John, and Bessie is one ofN cows (1 ≤ N ≤ 50,000) running for President. Before the election actually happens, however, Bessie wants to determine who has the best chance of winning.

The election consists of two rounds. In the first round, the K cows (1 ≤K ≤ N) cows with the most votes advance to the second round. In the second round, the cow with the most votes becomes President.

Given that cow i expects to get A_i votes (1 ≤ A_i ≤ 1,000,000,000) in the first round and B_i votes (1 ≤B_i ≤ 1,000,000,000) in the second round (if he or she makes it), determine which cow is expected to win the election. Happily for you, no vote count appears twice in theA_i list; likewise, no vote count appears twice in the B_i list.

Input

* Line 1: Two space-separated integers: N and K
* Lines 2..N+1: Line i+1 contains two space-separated integers: A_i andB_i

Output

* Line 1: The index of the cow that is expected to win the election.

Sample Input

5 33 109 25 68 46 5

Sample Output

5

Source

USACO 2008 January Bronze

 

answer：

#include"stdio.h"#include"cstring"#include"iostream"#include"algorithm"using namespace std;struct node{int a;int b;int flag;}vote[50005];bool cmp(const node &a1,const node &a2){return a1.a<a2.a;}int main(int argc, char* argv[]){ int n,k;int i,j,max,temp;max=0;while(cin>>n>>k){for(i=1;i<=n;i++){cin>>vote[i].a>>vote[i].b;vote[i].flag=i;}sort(vote+1,vote+n+1,cmp);for(j=n;j>n-k;j--){if(vote[j].b>max){max=vote[j].b;temp=vote[j].flag;}}cout<<temp<<endl;}return 0;}